Problem 44363. Is this is a Tic Tac Toe X Win?

Created byDoug Hull

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{“关系”：[{“ RelativeType”：“ http：//schemas.mathworks.com/matlab/matlab/code/2013/relationships/document'“：” /matlab/document.xml“}，{“ RelatessType”：“ http：//schemas.mathworks.com/matlab/matlab/code/2013/relationships/outputs/output”，“ targetMode”，“ targetMode”：“ targetMode”：“：”“ RID2”，“ TARGET”：“/MATLAB/output.xml”}]，“ parts”：[{“ parturi”：“/matlab/document.xml”，“关系”：[]：[]，“ contentType”：“：”：“”application/vnd.mathworks.matlab.code.document+xml“，” content“：” <？xml版本= \“ 1.0 \” encoding = \“ utf-8 \”？> \ n <w：document xmlns：w documn xmlns：w= \“ http：//schemas.openxmlformats.org/wordprocessingml/2006/main \”> <w：body> <w：p> <w：p> <w：ppr> <w：pstyle w：pstyle w：pstyle w：val = \ \ v \ \'> </w：ppr> <w：r> <w：t>对于</w：t> </w：r> <w：r> <w：t> </w：t> </w：t> </w：r> <w：超链接w：doclocation = \“ https：//en.wikipedia.org/wiki/wiki/tic-tac-toe \”> <w：r> <w：t>W：t> </w：r> </w：超链接> <w：r> <w：t>我们将在矩阵m。</w：t> </w：r> </w：p> <w：p> <w：ppr> <w：pstyle w：val = \“ text \”/> </w：ppr> <w：r> <w：t> for这个游戏：</w：t> </w：r> </w：p> <w：p> <w：ppr> <w：pstyle w：val = \“ text \”/> </w：ppr> <w：ppr> <w：r> <w：t> </w：t> </w：r> </w：p> <w：p> <w：ppr> <w：pstyle w：val = \ \“ text \”/> </w：ppr> <w：r> <w：t>我们将以此为：</w：t> </w：r> </w：p> <w：p> <w：p> <w：：ppr> <w：pstyle w：val = \“代码\”/> </w：ppr> <w：r> <w：t> <！[cdata [-1 1 1 1 \ n 1 -1 -1 -1 -1 -1\ n 1 -1 -1]]]> </w：t> </w：r> </w：p> <w：p> <w：ppr> <w：pstyle w：val = \ \“ text \ \”“/> </w：ppr> <w：r> <w：t>如果有空白的正方形，它们将为0; </w：</w：t> </w：r> </w：p> <：p> <w：p> <w：ppr> <w：pstyle w：val = \“ text \”/> </w：ppr> <w：r> <w：t>对于这个挑战，给定游戏状态，x（1）在任何行，列或主要对角线上连续三个？}，{“ parturi”：“/matlab/output.xml”，“ contentType”：“ text/xml”，“ content”：“ <？xml版本= \” 1.0 \“ 1.0 \” encoding = \“ utf-8 \” standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

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Last解决方法nsubmitted on May 16, 2022

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Sean de Wolskion 17 Oct 2017

解决方法n 7 should be correct. The diagonal of -1s is a valid win.

Hope all is well with you, Doug!

Ned Gulleyon 17 Oct 2017

@Sean, I think Doug's got it right. He's asking only if the X side (that is +1) is in a winning position. In test 7, the O side (-1) is in a winning position. So the answer given is correct.

解决方法n Comments

解决方案6617759

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Jan Orwaton 1 Oct 2021

with a little help of magic ;)

解决方法n 5147612

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李君on 23 Mar 2021

sum could not return the sum of all elements

解决方法n 2752336

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2 Comments

Nghia Huynhon 28 Jul 2020

Test 7 should return true. There is a diagonal of -1.

goc3on 29 Sep 2020

No. See Ned's comment and read the problem description again.

解决方法n 1384243

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1 Comment

Danielon 18 Dec 2017

Shouldn't Test 7 be y_correct = 1?

解决方法n 1380949

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1 Comment

Michal Dobaion 15 Dec 2017

To be fair, you didn't mention anything about anti-diagonal in your problem description (test no. 4). Or am I missing something?

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Problem 44363. Is this is a Tic Tac Toe X Win?

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