方向余弦矩阵风角度

$$\begin{array}{l}\left(\begin{array}{c}o{x}_3\\ o{y}_3\\ o{z}_3\end{array}\right]=DC{米}_{we}\left(\begin{array}{c}o{x}_0\\ o{y}_0\\ o{z}_0\end{array}\right]\\ \\ \left(\begin{array}{c}o{x}_3\\ o{y}_3\\ o{z}_3\end{array}\right]=\left(\begin{array}{ccc}1& 0& 0\\ 0& \mathrm{因为}\mu & 罪\mu \\ 0& -罪\mu & \mathrm{因为}\mu \end{array}\right]\left(\begin{array}{ccc}\mathrm{因为}\gamma & 0& -罪\gamma \\ 0& 1& 0\\ 罪\gamma & 0& \mathrm{因为}\gamma \end{array}\right]\left(\begin{array}{ccc}\mathrm{因为}\chi & 罪\chi & 0\\ -罪\chi & \mathrm{因为}\chi & 0\\ 0& 0& 1\end{array}\right]\left(\begin{array}{c}o{x}_0\\ o{y}_0\\ o{z}_0\end{array}\right]\end{array}$$

$$DC{米}_{we}=\left(\begin{array}{ccc}\mathrm{因为}\gamma \mathrm{因为}\chi & \mathrm{因为}\gamma 罪\chi & -罪\gamma \\ (罪\mu 罪\gamma \mathrm{因为}\chi -\mathrm{因为}\mu 罪\chi )& (罪\mu 罪\gamma 罪\chi +\mathrm{因为}\mu \mathrm{因为}\chi )& 罪\mu \mathrm{因为}\gamma \\ (\mathrm{因为}\mu 罪\gamma \mathrm{因为}\chi +罪\mu 罪\chi )& (\mathrm{因为}\mu 罪\gamma 罪\chi -罪\mu \mathrm{因为}\chi )& \mathrm{因为}\mu \mathrm{因为}\gamma \end{array}\right]$$

$$\begin{array}{l}\mu =\text{:}\left(\frac{DC米(2,3)}{DC米(3,3)}\right)\\ \\ \gamma =\text{印度历的7月}\left(-DC米(1,3)\right)\\ \\ \chi =\text{:}\left(\frac{DC米(1,2)}{DC米(1,1)}\right)\end{array}$$